sort list based on another list java

Any suggestions? 1. Rather than using a list to get values from the map, well be using LinkedHashMap to create the sorted hashmap directly. not if you call the sort after merging the list as suggested here. Overview. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. DigitalOcean makes it simple to launch in the cloud and scale up as you grow whether youre running one virtual machine or ten thousand. Note: the key=operator.itemgetter(1) solves the duplicate issue, zip is not subscriptable you must actually use, If there is more than one matching it gets the first, This does not solve the OPs question. (This is a very old answer!). I want to sort listA based on listB. rev2023.3.3.43278. Find centralized, trusted content and collaborate around the technologies you use most. As each pair of strings are passed in for comparison, convert them into ints using originalList.indexOf, except that if the index is -1, change the index to originalList.size() Compare the two ints. Why is "1000000000000000 in range(1000000000000001)" so fast in Python 3? Wed like to help. How to match a specific column position till the end of line? HashMap entries are sorted according to String value. This method will also work when both lists are not identical: Problem : sorting a list of Pojo on the basis of one of the field's all possible values present in another list. Note that you can shorten this to a one-liner if you care to: As Wenmin Mu and Jack Peng have pointed out, this assumes that the values in X are all distinct. I like having a list of sorted indices. Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Sort a list of Object according to custom priority of value in the Object JAVA 11, sort list of object on java 8 with custom criteria, Sort list based on specific order in java, (Java) Using lambda as comparator in Arrays.sort, How can I sort a list based on another list values in Java, Android Java - I need to sort a list based on another list, Intersection and union of ArrayLists in Java. Ultimately, you can also just use the comparing() method, which accepts a sorting key function, just like the other ones. The most obvious solution to me is to use the key keyword arg. Linear Algebra - Linear transformation question. For example, when appendFirst is false below will be the output. Here is a solution that increases the time complexity by 2n, but accomplishes what you want. You can use this generic comparator to sort list based on the the other list. You weren't kidding. rev2023.3.3.43278. We are sorting the names according to firstName, we can also use lastName to sort. I think most of the solutions above will not work if the 2 lists are of different sizes or contain different items. if item.getName() returns null , It will be coming first after sorting. The solution below is the most efficient in this case: Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. If the elements are not comparable, it throws java.lang.ClassCastException. Stream.sorted() by default sorts in natural order. Just remember Zx and Zy are tuples. P.S. The method returns a comparator that imposes the reverse of the natural ordering. This can create unstable outputs unless you include the original list indices for the lexicographic ordering to keep duplicates in their original order. In this quick tutorial, we'll learn how to find items from one list based on values from another list using Java 8 Streams. The code below is general purpose for a scenario where listA is a list of Objects since you did not indicate a particular type. His title should have been 'How to sort a dictionary?'. How to make it come last.? my case was that I have list that user can sort by drag and drop, but some items might be filtered out, so we preserve hidden items position. HashMap in java provides quick lookups. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Sort an array according to the order defined by another array using Sorting and Binary Search: The idea is to sort the A1 [] array and then according to A2 [] store the elements. When we try to use sort over a zip object. 2013-2023 Stack Abuse. Other answers didn't bother to import operator and provide more info about this module and its benefits here. Learn more about Stack Overflow the company, and our products. What happens if you have in List1, 50, 40 30 , and in List2 50 45 42? Styling contours by colour and by line thickness in QGIS. [[name=a, age=age11], [name=a, age=age111], [name=a, age=age1], [name=b, age=age22], [name=b, age=age2], [name=c, age=age33], [name=c, age=age3]]. You are using Python 3. zip, sort by the second column, return the first column. Wed like to help. Here is my complete code to achieve this result: But, is there another way to do it? Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Sorting a list in Python using the result from sorting another list, How to rearrange one list based on a second list of indices, How to sort a list according to another list? You should instead use [x for (y,x) in sorted(zip(Y,X), key=lambda pair: pair[0])]. How can I randomly select an item from a list? How do I sort a list of dictionaries by a value of the dictionary? B:[2,1,0], And you want to load them both and then produce: Actually, List is an interface and most of the time we use one of its implementation like ArrayList or LinkedList etc. If so, how close was it? In this tutorial we will sort the HashMap according to value. In case of Strings, they're sorted lexicographically: If we wanted the newly sorted list saved, the same procedure as with the integers applies here: Check out our hands-on, practical guide to learning Git, with best-practices, industry-accepted standards, and included cheat sheet. Java List is similar to arrays except that the length of the list is dynamic and it comes in Java Collection framework. Sorting in Natural Order and Reverse Order In each iteration, follow the following step . An efficient solution is to first create the mapping from the ID in the ids (your desired IDs order) to the index in that list: And then sort your list of people by the order of their id in this mapping: Note: if a person has an ID that is not present in the ids, they will be placed first in the list. This is useful when your value is a custom object. Is there a single-word adjective for "having exceptionally strong moral principles"? Once you have a list of sorted indices, a simple list comprehension will do the trick: Note that the sorted index list can also be gotten using numpy.argsort(). Collections class sort() method is used to sort a list in Java. We've used the respective comparison approaches for the names and ages - comparing names lexicographically using compareTo(), if the age values are the same, and comparing ages regularly via the > operator. Sorting a Java list collection using Lambda expression Since Java 8 with Lambda expressions support, we can write a comparator in a more concise way as follows: 1 Comparator<Book> descPriceComp = (Book b1, Book b2) -> (int) (b2.getPrice () - b1.getPrice ()); How can I check before my flight that the cloud separation requirements in VFR flight rules are met? Then we sort the list. Let's save this result into a sortedList: Here we see that the original list stayed unmodified, but we did save the results of the sorting in a new list, allowing us to use both if we need so later on. This is an old question but some of the answers I see posted don't actually work because zip is not scriptable. more_itertools has a tool for sorting iterables in parallel: I actually came here looking to sort a list by a list where the values matched. - the incident has nothing to do with me; can I use this this way? That's right but the solutions use completely different methods which could be used for different applications. We can also pass a Comparator implementation to define the sorting rules. The signature of the method is: The class of the objects compared by the comparator. The signature of the method is: It also returns a stream sorted according to the provided comparator. To subscribe to this RSS feed, copy and paste this URL into your RSS reader. Here's a simple implementation of that logic. zip, sort by the second column, return the first column. Java Sorting Java Sorting Learn to use Collections.sort () method to sort a list of objects using some examples. As you can see from the output, the linked list elements are sorted in ascending order by the sort method. Your compare methods are currently doing: This can be written more concisely with the built-in Double.compare (since Java 7), which also properly handles NaN, -0.0 and 0.0, contrary to your current code: Note that you would have the same implementation for the Comparator. If values in the HashMap are of type Integer, the code will be as follows : Here HashMap values are sorted according to Integer values. The best answers are voted up and rise to the top, Not the answer you're looking for? Python. Assuming that the larger list contains all values in the smaller list, it can be done. JavaTpoint offers too many high quality services. This will sort all factories according to their price. There is a difference between the two: a class is Comparable when it can compare itself to another class of the same type, which is what you are doing here: one Factory is comparing itself to another object. Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. All rights reserved. @RichieV I recommend using Quicksort or an in-place merge sort implementation. The solution below is simple and does not require any imports. The Comparator.comparing () method accepts a method reference which serves as the basis of the comparison. Stop Googling Git commands and actually learn it! If we talk about the working of this method, then the method works on ASCII values. Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my We will also learn how to use our own Comparator implementation to sort a list of objects. Can I tell police to wait and call a lawyer when served with a search warrant? Though it might not be obvious, this is exactly equivalent to, This is correct, but I'll add the note that if you're trying to sort multiple arrays by the same array, this won't neccessarily work as expected, since the key that is being used to sort is (y,x), not just y. i.e., it defines how two items in the list should be compared. Originally posted by David O'Meara: Then when you initialise your Comparator, pass in the list used for ordering. Another alternative, combining several of the answers. How to sort one list and re-sort another list keeping same relation python? How can I randomly select an item from a list? The java.Collections.sort () method is also used to sort the linked list, array, queue, and other data structures. Thanks for contributing an answer to Code Review Stack Exchange! The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup, Sorting Each Entry (code review + optimization), Sorting linked list with comparator in Java, Sorting a list of numbers, each with a character label, Invoking thread for each item in list simultaneously and returning value in Java, Sort a Python list of strings where each item is made with letters and numbers. Something like this? In Java how do you sort one list based on another? rev2023.3.3.43278. Note also, that the SortedDependingList does currently not allow to add an element from listA a second time - in this respect it actually works like a set of elements from listA because this is usually what you want in such a setting. Get tutorials, guides, and dev jobs in your inbox. There are at least two good idioms for this problem. For bigger arrays / vectors, this solution with numpy is beneficial! I like having a list of sorted indices. A:[c,b,a] How to remove an element from a list by index, Sorting an array of objects by property values, String formatting: % vs. .format vs. f-string literal. This is just an example, but it demonstrates an order that is defined by a list, and not the natural order of the datatype: Now, let's say that listA needs to be sorted according to this ordering. To learn more about comparator, read this tutorial. In java 6 or lower, you need to use. If we sort the Users, and two of them have the same age, they're now sorted by the order of insertion, not their natural order, based on their names. You get paid; we donate to tech nonprofits. The signature of the method is: In the following example, we have used the following methods: The reverseOrder() is a method of Comparator interface which is defined in java.util package. @Debacle What operations are allowed on the backend over listA? The below example demonstrates the concept of How to sort the List in Java 8 using Lambda Expression. The Collections (Java Doc) class (part of the Java Collection Framework) provides a list of static methods which we can use when working with collections such as list, set and the like. Making statements based on opinion; back them up with references or personal experience. This is a very nice way to sort the list, and to clarify, calling with appendFirst=true will sort the list as [d, c, e, a, b], @boxed__l: It will sort the elements contained in both lists in the same order and add at the end the elements only contained in A. Making statements based on opinion; back them up with references or personal experience. Check out our offerings for compute, storage, networking, and managed databases. Do I need to loop through them and pass them to the compare method? This is quite inefficient, though, and you should probably create a Map from listA to lookup the positions of the items faster. How do I read / convert an InputStream into a String in Java? Once we have the list of values in a sorted manner, we build the HashMap again based on this new list. Note that you can shorten this to a one-liner if you care to: As Wenmin Mu and Jack Peng have pointed out, this assumes that the values in X are all distinct. Thanks for learning with the DigitalOcean Community. So we pass User::getCreatedOn to sort by the createdOn field. Thanks for contributing an answer to Code Review Stack Exchange! As for won't work..that's right because he posted the wrong question in the title when he talked about lists. The Collections class has two methods for sorting a list: The sort() method sorts the list in ascending order, according to the natural ordering of its elements. You are using Python 3. What do you mean when you say that you're unable to persist the order "on the backend"? My lists are long enough to make the solutions with time complexity of N^2 unusable. For Action, select Filter the list, in-place. There are a few of these built-in comparators that work with numbers (int, double, and long) - comparingInt(), comparingDouble(), and comparingLong(). If a law is new but its interpretation is vague, can the courts directly ask the drafters the intent and official interpretation of their law? I can resort to the use of for constructs but I am curious if there is a shorter way. A example will show this. We can sort the entries in a HashMap according to keys as well as values. Starting with the example input you provided: This is also known as the Schwartzian_transform after R. Schwartz who popularized this pattern in Perl in the 90s: Note that in this case Y and X are sorted and compared lexicographically. Why is this sentence from The Great Gatsby grammatical? It is stable for an ordered stream. Sorting a 10000 items list 100 times improves speed 140 times (265 ms for the whole batch instead of 37 seconds) on my unit tests. The solution below is the most efficient in this case: Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Although I am not entirely sure exactly what the OP is asking for, I couldn't help but come to this conclusion as well. If you already have a dfwhy converting it to a list, process it, then convert to df again? Excuse any terrible practices I used while writing this code, though. I have a list of ordered keys, and I need to order the objects in a list according to the order of the keys. Theoretically Correct vs Practical Notation, Bulk update symbol size units from mm to map units in rule-based symbology. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. Maybe you can delete one of them. I mean swapItems(), removeItem(), addItem(), setItem() ?? good solution! Sorting for String values differs from Integer values. In this tutorial, we will learn how to sort a list in the natural order. Once streamed, we can run the sorted() method, which sorts these integers naturally. Now it actually works. When we compare null, it throws NullPointerException. One with the specific order the lists should be in (listB) and the other has the list of items (listA). Overview to Sorting Stream and List on Multiple Fields Using Java 8 We perform sorting on stream and list of objects using the multiple fields using the Comparators and Comparator.thenComparing () method. The collect() method is used to receive elements from a stream and stored them in a collection. For example, the following code creates a list of Student and in-place . That way, I can sort any list in the same order as the source list. The best answers are voted up and rise to the top, Not the answer you're looking for? It also doesn't care if the List R you want to sort contains Comparable elements so long as the other List L you use to sort them by is uniformly Comparable. Sorting HashMap by Value Simple Example. From simple plot types to ridge plots, surface plots and spectrograms - understand your data and learn to draw conclusions from it. Can airtags be tracked from an iMac desktop, with no iPhone? This method will also work when both lists are not identical: /** * Sorts list objectsToOrder based on the order of orderedObjects. Why is this sentence from The Great Gatsby grammatical? Once sorted, we've just printed them out, each in a line: If we wanted save the results of sorting after the program was executed, we would have to collect() the data back in a Collection (a List in this example), since sorted() doesn't modify the source. Working on improving health and education, reducing inequality, and spurring economic growth? Linear Algebra - Linear transformation question, Acidity of alcohols and basicity of amines, Is there a solution to add special characters from software and how to do it. Originally posted by David O'Meara: Then when you initialise your Comparator, pass in the list used for ordering. Sort a List of Integers 5 1 List<Integer> numbers = Arrays.asList(6, 2, 1, 4, 9); 2 System.out.println(numbers); 3 4 numbers.sort(Comparator.naturalOrder()); 5 System.out.println(numbers);. more_itertools has a tool for sorting iterables in parallel: I actually came here looking to sort a list by a list where the values matched. Maybe you can delete one of them. If a law is new but its interpretation is vague, can the courts directly ask the drafters the intent and official interpretation of their law? 2. Another alternative, combining several of the answers. Do roots of these polynomials approach the negative of the Euler-Mascheroni constant? The nature of simulating nature: A Q&A with IBM Quantum researcher Dr. Jamie We've added a "Necessary cookies only" option to the cookie consent popup. Most of the solutions above are complicated and I think they will not work if the lists are of different lengths or do not contain the exact same items. Then when you initialise your Comparator, pass in the list used for ordering. Find centralized, trusted content and collaborate around the technologies you use most. Mail us on [emailprotected], to get more information about given services. A Comparator can be passed to Collections.sort () or List.sort () method to allow control over the sort order. Why does Mister Mxyzptlk need to have a weakness in the comics? Follow Up: struct sockaddr storage initialization by network format-string. This can be elegantly solved with guava's Ordering.explicit: The last version of Guava thas supports Java 6 is Guava 20.0: First create a map, with sortedItem.name to its first index in the list. The most obvious solution to me is to use the key keyword arg. Guide to Java 8 Collectors: groupingByConcurrent(), Java 8 - Difference Between map() and flatMap(), Java: Finding Duplicate Elements in a Stream, Java - Filter a Stream with Lambda Expressions, Guide to Java 8 Collectors: averagingDouble(), averagingLong() and averagingInt(), Make Clarity from Data - Quickly Learn Data Visualization with Python, // Constructor, getters, setters and toString(), Sorting a List of Integers with Stream.sorted(), Sorting a List of Integers in Descending Order with Stream.sorted(), Sorting a List of Strings with Stream.sorted(), Sorting Custom Objects with Stream.sorted(Comparator

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